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Do most music CDs have 12 tracks?This might sound like some wild conspiracy theory, but I'm looking at my music collection and it sure seems like most of them have exactly 12 tracks, no more, no less. Is there some marketing reason this would be the case, or am I witness to some great conspiracy? :-) Don't panic! There's no magic to it. A music CD can hold 60-70 minutes of music and the average pop song is about 5 minutes long. Do the math and you'll see that gives you about 12 songs per CD. But I figured I'd do a bit of math here too. I have about 425 CDs in my music library, a wide range of genres, from country to classical, jazz to blues, and here's what I found: 428 albums analyzed The results:
That is, 65 of the 428 albums have 10 tracks, 56 have 12 tracks, 50 have 11 tracks, 41 have 9 tracks, and so on. Percentage-wise, this means that less than 15% of my 428 tested CDs have exactly 12 tracks, but averaging everything out, yes, the average music CD has 12.54 tracks. So there's your answer. No conspiracy theory involved! :-) How I did these calculationsFor those of you who would like to analyze your own iTunes library, here's how I did these calculations. I popped open a Terminal window on my Mac, moved into my "iTunes Music" folder within my "Music" folder, and... $ find . -type d -mindepth 2 -print | wc -l
428 The predicate "-type d" is directories, so that tells me the number of Cds, and $ find . -type f -mindepth 2 -print | wc -l
5369 That's the number of individual tracks across all those CDs. This means, by the way, that the average CD in my library, at least, has 12.54 tracks. So maybe there is some sort of conspiracy! To figure out how many tracks there are per CD is a bit more tricky. To accomplish this, I actually wrote a short shell script: #!/bin/sh
cd "/Users/taylor/Music/iTunes/iTunes Music" for directory in $( find . -type d -mindepth 2 -print | sed 's/ /_-_/g' ) exit 0 When run it lists tracks and albums: $ tracks-per-song.sh | head
14 tracks: ./10,000 Maniacs/MTV Unplugged 12 tracks: ./10cc/Greatest Hits 1972-78 10 tracks: ./Acoustic Alchemy/Blue Chip 9 tracks: ./Acoustic Alchemy/Red Dust & Spanish Lace 9 tracks: ./Acoustic Alchemy/Reference Point 12 tracks: ./Adrian Legg/Mrs. Crowe's Blue Waltz 6 tracks: ./Al Di Meola/Elegant Gypsy 9 tracks: ./Al Di Meola, Paco de Lucia & John McLaughlin/The Guitar Trio 11 tracks: ./Al DiMeola/Splendido Hotel 11 tracks: ./Al Jarreau/All I Got When I comment out the echo line and just output the number of tracks as a number with the wc command, I can easily slip the script into a typical collation sequence: $ tracks-per-song.sh | sort | uniq -c | sort -rn
65 10 56 12 50 11 41 9 25 8 24 15 etc etc etc Classic Unix command line stuff! :-)
Categorized:
Shell Script Programming
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Unix and Linux Help
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d) None of the Above
(Article 6682,
Written by Dave Taylor)
Tagged: apple itunes, music cds, shell script programming Previous: How do I put music on my Apple iPod? Next: How do I force Boot Camp to boot into Mac OS X? Subscribe!
Thanks for this one, Dave - it may well help me with a plan I have to make playlists of all the 'singles' I have accumulated over the years. Can the nr of tracks, for example 46 (aac, so cd language) be a problem for some cd players?.. By what reason? And does -R or +R does ast old players. A same brand -R cd she before received with a 23 tracks cd, labled with #9, and later this of same type -R and brand, labled #1 with 46 tracks; do i need to split. I heard of a pro-blem at 99 tracks.. Apart; an older cd-midiset in a chuch eyed though modern (with needles though) and a portable cd-radio set both did not accept or readed it as 'empty' or 'er'(error).., my laptop pc, my midiset, my portable radio-cd did accept and play splendid the stuff, before and after!! ARE there different planet-worlds ?? Thanks for the information. I was Box Car Willie's promotion manager for many years. The USA had nothing to do with him for a very long time. We hit it big in Europe and Australia, then came the good ol' USA. find: warning: you have specified the -mindepth option after a non-option argument -type, but options are not positional (-mindepth affects tests specified before it as well as those specified after it). Please specify options before other arguments. Running Ubuntu 8.04, I get this error while executing bash asdf.sh, with the echo commented, if it's commented it runs perfectly... Posted by: toor at December 7, 2009 12:35 AMActually, there is a conspiracy behind why most albums in the past have 12 or less tracks. When bands have contracts with major record labels, the standard contract has a cap on the amount of tracks the band can receive mechanical royalties on, regardless of how many tracks are on the album. The cap is usually 12, but sometimes 11 or 10. So most bands don't see the point in including extra tracks if they are not getting paid for it. Also why you see alot of albums with say 12 original tracks and a couple of covers. Because the covers are paid under performance not mechanical royalties. Posted by: Elizabeth at January 20, 2012 11:09 PMI have something to say, now that you mention it, but ...
I do have a comment, now that you mention it!
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